ANSWER
10.13 J
EXPLANATION
Given:
• the mass of the squirrel, m = 380g = 0.38kg
,• the distance of the pushups, d = 8.5cm = 0.085m
,• repetitions = 32
Unknown:
• total work done by the squirrel while moving upward, W
We know that the work done by a force F during a distance d is,
[tex]W=F\cdot d[/tex]In this case, we can assume that the force is the gravity force,
[tex]F_g=m\cdot g=0.38\operatorname{kg}\cdot9.8m/s=3.724N[/tex]The work done by the squirrel in one pushup is,
[tex]W_1=F_g\cdot d=3.724N\cdot0.085m=0.31654J[/tex]The work done for 32 pushups is,
[tex]W=32W_1=32\cdot0.31654J\approx10.13J[/tex]Rounded to the nearest hundredth, it is 10.13 J.