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29-10-2022
Mathematics

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If p(x)=6(x^2 + 2) + 13, what is the value of p(15)?A 1375B 205C 1747D 1365

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NimratY48963 NimratY48963

29-10-2022

p(x) = 6(x² + 2) + 13

To find p(15) you have to replace x = 15 into the equation, as follows:

p(15) = 6(15² + 2) + 13

p(15) = 6(225 + 2) + 13

p(15) = 6(227) + 13

p(15) = 1362 + 13

p(15) = 1375

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