Given: Given a triangle ABC with AB = AC. ∠C = 3x - 1 and ∠A = 2x + 10.
Required: Measure of angle A.
Explanation:
Since AB = AC, therefore
∠A = ∠C
Since angle opposite to equal sides of a triangle are equal.
Therefore,
[tex]\begin{gathered} 2x+10=3x-1 \\ 3x-2x=10+1 \end{gathered}[/tex]
So
[tex]x=11[/tex]
Therefore,
[tex]\begin{gathered} \angle A=2(11)+10=22+10 \\ \angle A=32\degree \end{gathered}[/tex]
Final Answer: Option C is correct.
