Respuesta :

[tex]\begin{gathered} f(x)=\frac{1}{(x-3)}-12 \\ g(x)=\frac{1}{x} \end{gathered}[/tex]

f(x) has a vertical asymptote at x = 3, while g(x) has a vertical asymptote at x = 0.

f(x) has a horizontar asymptote at y = -12, while g(x) has a horizontal asymptote at y = 0.

Therefore, the graph of f(x) is the graph of g(x) shifted 12 units down and 3 units right

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