The given inequalities are
[tex]\begin{gathered} 3x+4>13 \\ 4x-4<-24 \end{gathered}[/tex]
Let us start by 12t inequality,
Subtract 4 from each side
[tex]\begin{gathered} 3x+4-4>13-4 \\ 3x>9 \end{gathered}[/tex]
Divide each side by 3
[tex]\begin{gathered} \frac{3x}{3}>\frac{9}{3} \\ x>3 \end{gathered}[/tex]
For the 2nd inequality
Add 4 to each side
[tex]\begin{gathered} 4x-4+4<-24+4 \\ 4x<-20 \end{gathered}[/tex]
Divide each side by 4
[tex]\begin{gathered} \frac{4x}{4}<\frac{-20}{4} \\ x<-5 \end{gathered}[/tex]
We will represent these solutions on the number line
The solution of the compound inequality is
x < -5 and x > 3
You have to end the lines with arrows
