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Assume you have a normal distribution with a mean of 75 and a standard deviation of 14. Find the Z-Score of 62, rounding your answer to the nearest HUNDREDTH.

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STEP - BY - STEP EXPLANATION

What to find?

The z-score of 62

Given:

mean(μ) = 75

Standard deviation (σ) = 14

x- = 62

Step 1

Recall the formula for z - score.

[tex]Z=\frac{x-\mu}{\sigma}[/tex]

Step 2

Substitute the values into the formula and simpl

[tex]Z=\frac{62-75}{14}[/tex]

[tex]\approx-0.93[/tex]

ANSWER

-0.93

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