We know that the total of seats for this case are 61000 so we have the following equation:
[tex]A+B+C=61000[/tex]We also know that the number of seats in Secton A equals the total number of seats in sections B and C so then A=B+C
[tex]A+A=61000[/tex]Then the value of A =30500
Now we can create a function for the cost and we got:
[tex]3436000=85A+30B+25C[/tex]Replacing the value of A we got:
[tex]30B+25C=843500[/tex]And rewriting the first equation we got:
[tex]B+C=30500[/tex]Solving for B we got: B=30500-C and replacing in the before equation we got:
[tex]30(30500-C)+25C=843500[/tex]And solving for C we got:
[tex]-5C=843500-915000[/tex][tex]C=\frac{71500}{5}=14300[/tex]