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If a cooler contains six cola, two grape, two orange, and four lemon-lime sodas, what is the probability of selecting an orange, drinking it, then selecting a lemon-lime for your friend? Write your answer as a percent rounded to the nearest whole number.43%3%4%

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Hello

The total numbers of drinks in the cooler is

[tex]6+2+2+4=14[/tex]

The probability of selecting an orange drink is

[tex]\frac{2}{14}=\frac{1}{7}[/tex]

Since this is an example of probability without replacement,

When you're selecting a lime, the probability becomes

[tex]\frac{4}{13}[/tex]

Now the probability of selecting a lemon-lime would be

[tex]\frac{4}{13}\times\frac{1}{7}=\frac{4}{91}=0.043956\times100=4.39\text{ \%}\approx4\text{ \%}[/tex]

The answer to this question is 4%

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