Given
[tex]a_n=a_1+d\mleft(n-1\mright)[/tex]where
a₁ = 16 and d = -3
We want to find the 10th term of the sequence, this means: we want to find a₁₀.
Since aₙ, for a₁₀ n = 10. Then we replace in the equation:
a₁ = 16, d = -3 and n = 10.
[tex]\begin{gathered} a_n=a_1+d\mleft(n-1\mright) \\ \downarrow \\ a_{10}=16-3(10-1) \\ a_{10}=16-3\cdot9=16-27 \\ a_{10}=-11 \end{gathered}[/tex]Answer: A. -11
