Light in a vacuum travels at a constant speed of 3x108 m/s. If the Moon's average distance from the Earth is 38324203 km, how long would it take for a beam of light to travel from the Earth, to the Moon, and back to the Earth again?

Question

contestada

Respuesta :

GildardoZ207574 GildardoZ207574 · Answer 1 · 2022-10-29T16:23:25+02:00

In this case we will use the next formula

[tex]s=\frac{d}{t}[/tex]

where s is the speed, d is the distance and t is the time

In ur case

s= 3x10^8 m/s

we multiply by two the distance given because it is the double of the distance

d=2(38324203 )=76648406 km

and then we need to transform it into m

d=7.66x10^10m

Then we substitute

[tex]3\times10^8=\frac{7.66\times10^{10}}{t}[/tex]

Then we isolate the t

[tex]t=\frac{7.66\cdot10^{10}}{3\cdot10^8}=255.5s[/tex]

ANSWER

t=255.5 s