We will first obtain the perimeter of the trapezium:
Thus, we have:
[tex]\begin{gathered} P=7+8+6+9+8 \\ P=38\operatorname{cm} \end{gathered}[/tex]
Hence, the surface area of the figure is:
[tex]\begin{gathered} S\mathrm{}A=(38\times6)+2\times\mleft\lbrace\frac{1}{2}(14+8\mright)7\} \\ S\mathrm{}A=228+7(14+8) \\ S\mathrm{}A=228+784 \\ SA=1012\operatorname{cm}^2 \end{gathered}[/tex]
