Given:
sin θ = 5/13
θ is in Quadrant II
Find: sec θ and tan θ
Solution:
Recall that the sine function follows the pattern:
[tex]sin\theta=\frac{opposite}{hypotenuse}=\frac{y}{r}[/tex]Therefore, from the given sin value, y = 5 and r = 13. Since the angle is found in quadrant II, the value of y is positive while the value of x should be negative.
Now, let's solve for the value of x using the formula below.
[tex]x=\sqrt{r^2-y^2}[/tex]
