Can you please help me with this math question number 10

We have the following equation,
[tex]16-2x=88[/tex]and we need to find x. Then, by subtracting 16 to both sides, we have
[tex]\begin{gathered} 16-16-2x=88-16 \\ 0-2x=72 \\ -2x=72 \end{gathered}[/tex]and by dividing both sides by -2, we get
[tex]\begin{gathered} x=\frac{72}{-2} \\ x=-\frac{72}{2} \end{gathered}[/tex]which gives
[tex]x=-36[/tex]Therefore, the answer is x= -36