Answer:
x · x · x · x · x · x · x
5+2
Given:
[tex]x^5\cdot x^2[/tex]
We can expand this as:
[tex]\begin{gathered} x^5=x\cdot x\cdot x\cdot x\cdot x \\ x^2=x\cdot x \\ \end{gathered}[/tex]
Therefore:
[tex]\begin{gathered} x^5\cdot x^2=(x\cdot x\cdot x\cdot x\cdot x)\cdot(x\cdot x) \\ =x\cdot x\cdot x\cdot x\cdot x\cdot x\cdot x \end{gathered}[/tex]
Now, according to the Product Rule of Exponents:
[tex]a^x\times a^y=a^{x+y}[/tex]
Applying this to our expression:
[tex]x^5\cdot x^2=x^{5+2}[/tex]
