Given the equation:
[tex](x+3)^2+y^2=25[/tex]
The given equation represents the equation of the circle
The general equation of the circle is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Where r is the radius and the center at the point ( h , k )
So, compare the given equation to the general form, we will get:
[tex]\begin{gathered} r^2=25 \\ r=\sqrt[]{25}=5 \\ \text{Center}=(h,k)=(-3,0) \end{gathered}[/tex]
The graph of the given equation is as the following image:
