Respuesta :

[tex]\begin{gathered} 1.x^2-4x+1\text{ a}=x^2\text{ or 1; b}=-4;\text{ c}=1 \\ h=\frac{-b}{2(a)} \\ h=\frac{-(-4}{2(1)} \\ h=\frac{4}{2} \\ h=2 \\ V(h,k) \\ K=\frac{4ac-b^2}{4a}=\frac{4(1)(1)-(-4)^2}{4(1)} \\ K=\frac{4-(16)}{4} \\ k=\frac{12}{4}=3;then\text{ } \\ V(2,3);\text{ X}=2\text{ and Y}=3 \\ \\ \\ \end{gathered}[/tex]

1.To find the vertex of the quadratic function we must apply the formula to find h which is equivalent to point x and then apply the formula to find K which is equivalent to point Y for the coordinates of the quadratic function.

2.For this, it is very important to know how to identify each of the values ​​of the quadratic equation for a, for b and for c .

3.It is important to know that when a negative number is raised to a power the result will be positive.

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