Solution:
Assuming you are rolling a standard 6-sided die with sides numbered 1 to 6, then there are 6 possible outcomes:
[tex]\lbrace1,2,3,4,5,6\rbrace[/tex]
now, note that 4 of these outcomes are greater than 2:
[tex]\lbrace3,4,5,6\rbrace[/tex]
So the probability of a roll greater than 2 is 4 out of 6, that is:
[tex]P(roll\text{ }>\text{ 2 ) =}\frac{4}{6}=\frac{2}{3}[/tex]
so that, the correct answer is:
[tex]\frac{2}{3}[/tex]
