Given:
The first plane is travelling 3.5 times as fast as the second plane.
After travelling in the same direction for 5.5 hours, they are 1265 miles apart.
To find:
The average speed of each plane.
Explanation:
Let x be the average speed of the second plane.
So, 3.5x be the average speed of the first plane.
We know that the distance formula is,
[tex]Distance=Speed\times Time[/tex]
After travelling in the same direction for 5.5 hours,
[tex]\begin{gathered} First\text{ plane's d}istance-Second\text{ planes's distance = 1265} \\ S_1T_1-S_2T_2=1265 \\ 3.5x(5.5)-x(5.5)=1265 \\ 19.25x-5.5x=1265 \\ 13.75x=1265 \\ x=\frac{1265}{13.75} \\ x=92mph \end{gathered}[/tex]
So, the average speed of the second plane is 92mph.
Therefore, the average speed of the first plane will be,
[tex]3.5(92)=322mph[/tex]
Final answer:
• The average speed of the first plane is 322mph.
,
• The average speed of the second plane is 92mph.
