ANSWER
[tex]\begin{equation*} 2.6\text{ }m\/s^2 \end{equation*}[/tex]EXPLANATION
Parameters given:
Initial velocity, u = 3.0 m/s
Final velocity, v = 12.0 m/s
Time elapsed, t = 3.5 s
To find the magnitude of the acceleration of the truck, apply the formula for acceleration:
[tex]a=\frac{v-u}{t}[/tex]Therefore, the acceleration of the truck is:
[tex]\begin{gathered} a=\frac{12.0-3.0}{3.5}=\frac{9}{3.5} \\ \\ a=2.6\text{ }m\/s^2 \end{gathered}[/tex]That is the acceleration to 1 decimal place.
