0.125L
According to the dilution formula
[tex]C_1V_1=C_2V_2[/tex]where:
• C1 and C2 are the ,concentrations
,• V1 and V2 are the, volumes
Given the following parameters
[tex]\begin{gathered} C_1=3.00M \\ C_2=1.25M \\ V_2=0.300L \end{gathered}[/tex]Requuired
Iniital volume V1
Substitute
[tex]\begin{gathered} V_1=\frac{C_2V_2}{C_1} \\ V_1=\frac{1.25\times0.3}{3.0} \\ V_1=0.125L \end{gathered}[/tex]Therefore the amount of volume required is 0.125L
