Answer:
[tex]y=\frac{2}{3}x-\frac{46}{3}[/tex]Step-by-step explanation:
A line perpendicular to another has a slope that is the negative reciprocal of the slope of the other line. Therefore, the slope of the line is -(-2/3)=2/3.
Therefore, for the given line using the slope-point form of the equation:
[tex]\begin{gathered} y+10=\frac{2}{3}(x-8) \\ y=\frac{2}{3}x-\frac{16}{3}-10 \\ y=\frac{2}{3}x-\frac{46}{3} \end{gathered}[/tex]