Given data
*The given height of the roof above the ground is h = 12.2 m
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The formula for the time taken by the ball to reach the ground is given as
[tex]t=\sqrt[]{\frac{2h}{g}}[/tex]
Substitute the known values in the above expression as
[tex]\begin{gathered} t=\sqrt[]{\frac{2\times12.2}{9.8}} \\ =1.58\text{ s} \end{gathered}[/tex]
Hence, the time taken by the ball to reach the ground is t = 1.58 s
