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Which of these expressions yields the speed of sound in air in SI units if the air temperature is 163 degrees Celsius? [Describe the properties of sound waves] 331.5 divided by 0.607 times 163 331.5 + 0.607 times 163 331.5 times 0.607 times 163

Respuesta :

Given:

the temperature of the air is

[tex]T=163\text{ C}[/tex]

Required: velocity of the wave in air

Explanation: At normal atmospheric pressure, the temperature dependence of the speed of wave is given by

[tex]v=331\text{ m/s +0.6 m/s}\times T[/tex]

Plugging the value of T in above relation we get

[tex]v=331\text{ m/s+ 0.6 m/s}\times163\text{ }[/tex]

Thus, the speed of the wave is

[tex]331\text{ m/s+ 0.607 times 163}[/tex]

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