As given by the question
There are given that the cone.
Now,
From the formula of volume of cone:
[tex]V=\frac{\pi\times r^2\times h}{3}[/tex]
Then,
From the given figure, there are given that height and diameter
So,
First, find the value of radius (r)
[tex]\begin{gathered} d=2r \\ r=\frac{d}{2} \\ r=\frac{8}{2} \\ r=4 \end{gathered}[/tex]
Then,
Put the value of r and h into the given formula:
[tex]\begin{gathered} V=\frac{\pi\times r^2\times h}{3} \\ V=\frac{3\times(4)^2\times6}{3} \\ V=\frac{3\times16^{}\times6}{3} \\ V=16^{}\times6 \\ V=96 \end{gathered}[/tex]
Hence, the value of volume of the cone is 96 ft^3
