The largest side of the triangle is 52.
Checking pythagoraus theorem,
[tex]\begin{gathered} 52^2=2704 \\ 21^2+47^2=441+2209 \\ =2650 \\ \text{Thus,} \\ 21^2+47^2\ne52^2 \end{gathered}[/tex]Thus, it is not a right angle triangle.
Thus, option (D) is correct.
