In this problem we have that
the point P is equidistant from the vertices of triangle
that means
PA=PB=PC
because
point P is not a incenter point
In this problem
the point P is the circumcenter
The circumcenter is equidistant from the three vertices, and so the common distance is the radius of a circle that passes through the vertices.
It is located by finding the point of intersection formed by the perpendicular bisectors of each of the sides of the triangle
Timothy's mistake was find out the circumcenter instead of the incenter
