There are 4 aces and 4 queens.
Total card are 52.
Thus required number of ways of choosing 3 aces is:
[tex]^4C_3=\frac{4!}{3!1!}=4[/tex]The number of ways of choosing 1 queen is:
[tex]^4C_1=\frac{4!}{1!3!}=4[/tex]Thus total nmber of ways is 4x4=16
The answer is D.16
