Respuesta :
Let o be the size of the object. Since the lens magnifies the object by 6.1 and the image is 3.33 m tall, then:
[tex]6.1\times o=3.33m[/tex]Divide both sides of the equation by 6.1 to find the value of o:
[tex]\begin{gathered} \frac{6.1\times o}{6.1}=\frac{3.33m}{6.1} \\ \Rightarrow o\approx0.546m \end{gathered}[/tex]Therefore, the original object is 0.546m tall.
Remember the following definition for the magnification of an optical instrument:
[tex]\text{magnification }=\frac{\text{image height}}{\text{ object height}}[/tex]Which can also be written using M for magnification, i for image height and o for the object height:
[tex]M=\frac{i}{o}[/tex]