Respuesta :

As per similar rule:

[tex]\text{ABCD}\approx\text{EFGH}[/tex]

So:

[tex]\begin{gathered} \frac{BC}{FG}=\frac{CD}{GH} \\ \frac{26}{10}=\frac{13}{x-7}^{} \\ x-7=\frac{10\times13}{26} \\ x-7=5 \\ x=12 \end{gathered}[/tex]

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