Answer:
The expression is given below as
[tex](3x^2y^{-3})^3[/tex]Step 1:
Apply the exponent rule below
[tex](a.b)^n=a^n.b^n[/tex]By applying the exponent rule, we will have
[tex]\begin{gathered} (3x^2y^{-3})^3 \\ =3^3\times x^{2\times3}\times y^{-3\times3} \\ =27x^6\times y^{-9} \\ \text{note:} \\ y^{-9}=\frac{1}{y^9} \\ =27x^6\times y^{-9} \\ =\frac{27x^6}{y^9} \end{gathered}[/tex]Hence,
The simplified expression will be
[tex]\frac{27x^6}{y^9}[/tex]