Given,
[tex]\begin{gathered} (f+g)x=f(x)+g(x) \\ f(x)=9x-5 \\ g(x)=1-x \end{gathered}[/tex]Expanding the terms,
[tex]\begin{gathered} (f+g)x=(9x-5)+(1-x) \\ =9x-5+1-x \\ =9x-x-5+1 \end{gathered}[/tex][tex](f+g)x=8x-4[/tex]Hence, (f + g)x is 8x - 4.
