There are 6 sub parts in the given circle.
In the 6 sub parts, Only one part is the green section.
Therefore, the probability that the spinner arrow will land in a striped green section is,
[tex]\begin{gathered} P(A)=\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} \\ P(A)=\frac{1}{6} \end{gathered}[/tex]In percentage,
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