If a circle has an area of 32 rt square feet, then a 135-degree sector of the circle has an area of blanksquare feet. Round to the nearest tenths place.

Given,
The area of the circle is,
[tex]32\pi[/tex][tex]\begin{gathered} \pi r^2=32\pi \\ r^2=32 \\ r=5.65 \end{gathered}[/tex]The area of the circle sector is,
[tex]\begin{gathered} S=\frac{r^2\theta}{2} \\ \text{ = }\frac{(5.65)^2\times(135)}{2} \\ \text{ = 37}.61 \end{gathered}[/tex]The area of the circle sector is 37.6 sq ft