You have the following equation given in the exercise:
[tex]\frac{1}{3}y=6(x-\frac{1}{6})[/tex]In order to solve for "y" in terms of "x", you can follow the steps shown below:
1. Apply the Distributive property, which states:
[tex]\begin{gathered} a(b+c)=ab+ac \\ a(b-c)=ab-ac \end{gathered}[/tex]Then:
[tex]\begin{gathered} \frac{1}{3}y=(6)(x)-(6)(\frac{1}{6}) \\ \\ \frac{1}{3}y=6x-1 \end{gathered}[/tex]2. Now you must apply the Multiplication property of equality by multiplying both sides of the equation by 3:
[tex]\begin{gathered} (\frac{1}{3}y)(3)=(6x-1)(3) \\ \\ y=18x-3 \end{gathered}[/tex]Therefore, the equation solved for "y" in terms of "x", is:
[tex]y=18x-3[/tex]