Use the sum and difference identities to rewrite the following expression as a trigonometric function of a single number.tan(100°) – tan(10)1 + tan(100°)tan (10)

Given the trigonometric function:
[tex]\frac{\tan 100-\tan 10}{1+\tan 100\tan 10}[/tex]According to the double angle rule in trigonometry identity;
[tex]\tan (A-B)=\frac{\tan A-\tan B}{1+\tan A\tan B}[/tex]Comparing both expressions, you can see that:
A = 100⁰
B = 10⁰
This shows that the given trigonometry identity is equivalent to:
[tex]\tan (100-10)=\frac{\tan100-\tan10}{1+\tan100\tan10}[/tex]Next is to write the trigonometry function tan(100-10) as a function of single number;
Since tan(100-10) = tan 90, hence;
[tex]\tan 90=\frac{\tan100-\tan10}{1+\tan100\tan10}[/tex]