Given the function below
[tex]g(x)=(x-4)^2[/tex]Therefore
[tex]y=(x-4)^2[/tex][tex]\begin{gathered} y=(x-4)(x-4) \\ y=x^2-4x-4x+16 \end{gathered}[/tex][tex]y=x^2-8x+16[/tex]Given the general equation of a quadratic function as:
[tex]\begin{gathered} y=ax^2+bx+c \\ c\rightarrow is\text{ the yintercept} \end{gathered}[/tex]Hence, the y-intercept of the function g(x) is 16
