Respuesta :

Given the point:

P(6, 0)

Under de translation we have:

[tex](x,y)\rightarrow(x-6,y-1)[/tex]

Substitute x = 6 and y = 0, so:

[tex]P^{\prime}(6-6,0-1)=P^{\prime}(0,-1)[/tex]

Answer:

[tex](0,-1)[/tex]