. A species of frog’s population grows 24% every year. Suppose 100 frogs are released into a pond.How many years will it take for there to be at least 1000 frogs?

Respuesta :

ANSWER

It will take 10.71 years for the frogs to grow from 100 to 1000

STEP-BY-STEP EXPLANATION:

Given information

The initial population of the frogs = 100

Percentage increase = 24%

The final population of the growth = 1000 frogs

time =?

Step 1: Write the general formula for calculating the size of a population

[tex]P=P_O(1+r)^t[/tex]

Where

P = Final population

Po = initial population

r = rate

t = time

Step 2= convert the growth rate from percentage to decimal

[tex]\begin{gathered} r\text{ = 24 \%} \\ r\text{ = }\frac{24}{100} \\ r\text{ = 0.24} \end{gathered}[/tex]

Step 3: Substitute the given data into the above formula and solve for t

[tex]\begin{gathered} 1000=100(1+0.24)^t \\ \text{Divide both sides by 100} \\ \frac{1000}{100}\text{ = }\frac{100}{100}(1+0.24)^t \\ 10=(1+0.24)^t \\ 10=(^{}1.24)^t \\ \text{Take the logarithms of both sides} \\ \text{log 10 = t log(1.24)} \\ 1\text{ = t }\times\text{ 0.0934} \\ 1\text{ = 0.0934t} \\ \text{Divide both sides by 0.0934} \\ \frac{1}{0.0934}\text{ = }\frac{\cancel{0.0934}t}{\cancel{0.0934}} \\ t\text{ = 10.71 years} \end{gathered}[/tex]

Hence, it will take 10.71 years for the frogs to grow from 100 to 1000