Respuesta :
Let the number of children be "c" and the number of adults be "a".
There are a total of 629 adults and children.
Thus, we can write an equation:
[tex]c+a=629[/tex]Price of each children admit is 1.25 and each child admit is 2.50 for a total of $1200.
Thus, we can write an equation to represent this information as:
[tex]1.25c+2.50a=1200[/tex]We can solve the system of 2 equations we got and find out the values of "a" and "c".
Solving the first equation for c:
[tex]\begin{gathered} c+a=629 \\ c=629-a \end{gathered}[/tex]We substitute it into second equation and figure out a:
[tex]\begin{gathered} 1.25c+2.50a=1200 \\ 1.25(629-a)+2.50a=1200 \\ 786.25-1.25a+2.50a=1200 \\ 1.25a=1200-768.25 \\ 1.25a=413.75 \\ a=\frac{413.75}{1.25} \\ a=331 \end{gathered}[/tex]Now, we simply find out c:
[tex]\begin{gathered} c=629-a \\ c=629-331 \\ c=298 \end{gathered}[/tex]Answer:
Children = 298Adults = 331