Given data:
* The velocity of the car is 13.6 m/s.
* The car stops in 0.321 m.
* The force exerted on the child of mass 21.2 kg is -6110 N.
* The mass of the child is 21.2 kg.
Solution:
The weight of the child is,
[tex]W=mg[/tex]
where m is the mass of the child, and g is the acceleration due to gravity,
Substituting the known values,
[tex]\begin{gathered} W=21.2\times9.8 \\ W=207.76\text{ N} \end{gathered}[/tex]
By dividing the force exerted on the child with the weight of the child,
[tex]\begin{gathered} \frac{F}{W}=\frac{6110}{207.76} \\ \frac{F}{W}=29.4 \\ F=29.4\times W \end{gathered}[/tex]
Thus, the force is 29.4 times the weight of the child.
