DamoriJ413283
DamoriJ413283
29-10-2022
Mathematics
contestada
Solve please. 4x^2-25
Respuesta :
JdN688337
JdN688337
29-10-2022
[tex]\begin{gathered} 4x^2-25=0 \\ 4x^2=25 \\ x^2=\frac{25}{4} \\ x=\sqrt[]{\frac{25}{4}} \\ x=\frac{\sqrt[]{25}}{\sqrt[]{4}} \\ x=\frac{5}{2} \\ or\text{ x=2.5} \end{gathered}[/tex]
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