Answer:
The energy stored in the spring = 11.79 Joules
Explanation:
The energy stored in a spring is given by the formula:
[tex]E=\frac{1}{2}kx^2[/tex]
where E is the energy
k is the spring constant
x is the extension
The length of the spring is extended by x₁ and x₂
The energy stored in the spring is therefore:
[tex]E=\frac{1}{2}k(x_1+x_2)^2[/tex]
x₁ = 22 cm
x₁ = 22/100
x₁ = 0.22 m
x₂ = 17 cm
x₂ = 17/100
x₂ = 0.17 m
The spring constant, k = 155 N/m
Substitute x₁ = 0.22 m, x₂ = 0.17 m, and k = 155 N/m into the formula for the energy. The energy stored in the spring is therefore calculated as follows
[tex]\begin{gathered} E=\frac{1}{2}(155)(0.22+0.17)^2 \\ E=0.5(155)(0.1521) \\ E=\text{ 11.79J} \end{gathered}[/tex]
The energy stored in the spring = 11.79 Joules
