Given:
[tex]e^{2-3x}=125[/tex]Required:
To find the value of x.
Explanation:
Consider
[tex]\begin{gathered} e^{2-3x}=125 \\ \\ -3x+2=\ln(125) \\ \\ -3x=\ln(125)-2 \\ \\ x=\frac{\ln(125)-2}{-3} \end{gathered}[/tex]Final Answer:
[tex]x=\frac{\ln(125)-2}{-3}[/tex]