Data:
Manoj did 1/10
Kumar did 1/8
Kiran did 1/20
How much work did they finish working together?
Add the fractions as follow:
[tex]\begin{gathered} \frac{a}{b}\pm\frac{c}{d}=\frac{ad\pm bc}{bd} \\ \\ \\ \frac{1}{10}+\frac{1}{8}=\frac{8+10}{80}=\frac{18}{80}=\frac{9}{40} \\ \\ \frac{9}{40}+\frac{1}{20}=\frac{180+40}{800}=\frac{220}{800}=\frac{11}{40} \end{gathered}[/tex]If the remaining part of the work is finished by Arun, what part of work is done by Arum?
Takes the total work as a unit (1), then subtract 11/40 from 1:
[tex]1-\frac{11}{40}=\frac{40-11}{40}=\frac{29}{40}[/tex]Then, Arum needs to do 29/40 part of the work to finish it,
