the sum of three numbers is 78. the second number is twice the first and the third is 3 times the first . find the number

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MarionaH590046 MarionaH590046 · Answer 1 · 2022-10-29T07:57:05+02:00

Given

The sum of three numbers is 78.

The second number is twice the first.

The third number is 3 times the first.

Explanation

Let the first number be x, second number be y and third number be z.

From the given condition , equations formed are

[tex]x+y+z=78.........................1[/tex][tex]y=2x.....................2[/tex][tex]z=3x............................3[/tex]

Substitute the values from the equation 2 and 3 in equation 1.

[tex]\begin{gathered} x+2x+3x=78 \\ 6x=78 \\ x=13 \end{gathered}[/tex]

Then the first number is 13 and second and third number is determined by substitute the value of x in equation 2 and 3,

[tex]\begin{gathered} y=2\times13=26 \\ z=3\times13=39 \end{gathered}[/tex]Answer

Hence the first number is 13, second number is 26 and third number is 39.