ANSWER
[tex]\frac{9}{2}g^4-18g^3+24g^2\text{ - 12g + 2}[/tex]
STEP-BY-STEP EXPLANATION
Area of a triangle is
[tex]\text{Area = }\frac{1}{2}bh[/tex]
Note: the base and the height are the same because it's an isosceles triangle
[tex]\text{Area = }\frac{1}{2}(3g^2\text{ - 6g + 2)}\cdot(3g^2\text{ - 6g + 2)}[/tex]
Let's expand the expression
[tex]\text{Area = }\frac{1}{2}(9g^4-18g^3+6g^2-18g^3+36g^2-12g+6g^2\text{ - 12g + 4)}[/tex][tex]undefined[/tex]
