To find the linear equation for this points:
(-10, 0) and (-8, 10), we will need to use the following expression to calculate the slope:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{10-0}{-8-(-10)} \\ m=\frac{10}{2} \\ m=5 \end{gathered}[/tex]A linear equation is represented by this expression in slope-intercept form:
[tex]\begin{gathered} y=mx+b \\ \text{where,} \\ m\text{ is the slope and b is the y-intercept.} \end{gathered}[/tex]Since we don't have the y-intercept, we can find the equation of the line by using the slope-point form:
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-0=5(x+10) \\ y=5x+50 \end{gathered}[/tex]