The solubility of a compound is 2.5 g in 100. mL of aqueous solution at 25°C. If we put 1.12 g of the compound in a 50.-mL volumetric flask at 25°C and add sufficient water to fill it to the 50.-mL mark, what kind of solution do we get-saturated or unsaturated?Explain.

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MaybleN135095 MaybleN135095

29-10-2022
Chemistry

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The solubility of a compound is 2.5 g in 100. mL of aqueous solution at 25°C. If we put 1.12 g of the compound in a 50.-mL volumetric flask at 25°C and add sufficient water to fill it to the 50.-mL mark, what kind of solution do we get-saturated or unsaturated?Explain.

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AdelynT55042 AdelynT55042 · Answer 1 · 2022-10-29T06:44:07+02:00

1) Saturated solution. A saturated solution contains the maximum amount of solute dissolved. The solubility of the compound is 2.5 g in 100 mL.

2) Find the concentration (percentage mass by volume) of the saturated solution

[tex]\%=\frac{mass\text{ }in\text{ }grams}{milliliters\text{ }of\text{ }solution}*100[/tex][tex]\%=\frac{2.5\text{ }g\text{ }}{100\text{ }mL}*100=2.5\%[/tex]

The concentration of the saturated solution is 2.5 %.

3) Find the concentration (percentage mass by volume) of the sample

[tex]\%=\frac{1.12\text{ }g}{50.\text{ }mL}*100=2.24\%[/tex]

The concentration of the sample (1.12g in 50. mL) is 2.24%. The concentration of the sample is lower than the saturated concentration. So, the solution is unsaturated.

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