Respuesta :

We have,

[tex]\begin{gathered} \cos x=\frac{adjacent\text{ side}}{hypotenuse} \\ \sin x=\frac{\text{opposite side}}{hypotenuse} \\ \tan x=\frac{oppositeside}{adjacent\text{ side}} \end{gathered}[/tex]

So here,

[tex]\begin{gathered} \cos x=\frac{d}{f} \\ \sin x=\frac{e}{f} \\ \tan x=\frac{e}{d} \end{gathered}[/tex]

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