What else would need to be congruent to show that ABC=XYZ by ASA?

For the triangle ABC to be equal to XYZ to be congruent by the ASA criterion, having the angles
[tex]\begin{gathered} \measuredangle A=\measuredangle X \\ \measuredangle C=\measuredangle Z \end{gathered}[/tex]We need the side that is between these angles to be equal, which is why the correct answer is:
[tex]\bar{AC}\cong\bar{XZ}[/tex]